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Why the circuit Current (I) decrease, when Inductance (L) or inductive reactance (XL) increases in inductive circuit?   Explain the statement that ” In Inductive circuit, when  Inductance (L) or inductive reactance (X L ) increases, the circuit Current (I) decrease”   OR Why the circuit Current (I) decrease, when   Inductance (L) or inductive reactance (X L ) increases in inductive circuit? Explanation: We know that,  I = V / R,  but in inductive circuit,  I = V/X L So Current in inversely proportional  to the Current ( in inductive circuit. Let ‘s check with an example..     Suppose, when Inductance (L) = 0.02H V=220, R= 10 Ω,  L=0.02 H , f=50Hz. X L  = 2πfL = 2 x 3.1415 x 50 x 0.02 = 6.28 Ω Z = √ (R 2 +X L 2 ) = √ (10 2  + 6.28 2 ) = 11.8 Ω I = V/Z = 220/11.8 =   18.64 A Now we increases Inductance (L) form 0.02 H to 0.04 H, V=2...

How to find The value of Burnt Resistor ( By three handy Methods ) Find The value of Burnt Resistor by Three Simple Methods  We can find the Values of  burnt resistors  by these three handy methods below. Method 1 Scarp the outer coating. Clean the Burnt Section of the resistor. Measure resistance from one end of the resistor to the damaged section. Again measure the resistance from damaged section to the other end of the resistor. Add these two value f resistances. This is the approximate value of Burnt resistor.  Just add a small value of resistance for damaged section i.e., suppose the value of burnt resistor was 1k Ω, but you got 970 Ω. So just add 30 Ω, and you will have 1k Ω. Also Read:  How to check a Capacitor by 4 Simple Methods Method 2 This method can also be used for finding the value of  burnt resistor(s) (also, may be applied on connected resistors in the circuit) in case if you don’t know about Resis...

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